This challenge gives us a python script with the flag split up and randomized and the hash of the correct flag:
from hashlib import blake2b
# piesele din steag sunt amestecate
flag = ['ea87f8}', 'h{c197a0', '644f0b26', '26fc5753', '7bd7bfd7', '3b7f75ca', 'db1dd753', '4adbd1f9', 'c800171e', 'abso-tec']
flag = "".join(flag).encode()
blake = blake2b()
blake.update(flag)
hashed = blake.hexdigest()
### valoarea originala a flagului hash-uit : f1596e539f988dc3bdf619258b4570671e9bbe71c94e7342336c4717970355c5858662150877711ecaa97372667a3a523939638d1793eb5fbf14013ef6ae8288
After making this absolutely HORRIBLE code I got the correct flag: abso-tech{c197a03b7f75ca7bd7bfd7db1dd7534adbd1f9c800171e26fc5753644f0b26ea87f8}.
from hashlib import blake2b
# piesele din steag sunt amestecate
flag = ['644f0b26', '26fc5753', '7bd7bfd7', '3b7f75ca', 'db1dd753', '4adbd1f9', 'c800171e']
# # # # # # # #
flag_start = 'abso-tech{c197a0'
flag_end = 'ea87f8}'
def find_flag():
for item in flag:
tmp1 = flag.copy()
tmp1.remove(item)
for item2 in tmp1:
tmp2 = tmp1.copy()
tmp2.remove(item2)
for item3 in tmp2:
tmp3 = tmp2.copy()
tmp3.remove(item3)
for item4 in tmp3:
tmp4 = tmp3.copy()
tmp4.remove(item4)
for item5 in tmp4:
tmp5 = tmp4.copy()
tmp5.remove(item5)
for item6 in tmp5:
tmp6 = tmp5.copy()
tmp6.remove(item6)
for item7 in tmp6:
tmp7 = tmp6.copy()
tmp7.remove(item7)
_flag = flag_start + item + item2 + item3 + item4 + item5 + item6 + item7 + flag_end
blake = blake2b()
_flag = _flag.encode('utf-8')
blake.update(_flag)
hashed = blake.hexdigest()
print(str(_flag) + " : " + hashed)
if hashed == "f1596e539f988dc3bdf619258b4570671e9bbe71c94e7342336c4717970355c5858662150877711ecaa97372667a3a523939638d1793eb5fbf14013ef6ae8288":
print("flag found!:" + str(_flag))
return
find_flag()
### valoarea originala a flagului hash-uit : f1596e539f988dc3bdf619258b4570671e9bbe71c94e7342336c4717970355c5858662150877711ecaa97372667a3a523939638d1793eb5fbf14013ef6ae8288